f(x) = 3x + 2 g(x) = x+3 / 2x + 1
calcular (f o g) (x)
f o g = g [f(x)] = g (3x + 2 ) = 3x+2+3 / 2(3x + 2) +1 = 3x+5 / 6x+5
calcula (g o f) (x)
f o g = f [g(x)] = f ( x+3 / 2x+1 ) = 3 ( x+3 / 2x+1 ) +2 = 7x+11 / 2x+1
